2b^2-4=28

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Solution for 2b^2-4=28 equation:


Simplifying
2b2 + -4 = 28

Reorder the terms:
-4 + 2b2 = 28

Solving
-4 + 2b2 = 28

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 2b2 = 28 + 4

Combine like terms: -4 + 4 = 0
0 + 2b2 = 28 + 4
2b2 = 28 + 4

Combine like terms: 28 + 4 = 32
2b2 = 32

Divide each side by '2'.
b2 = 16

Simplifying
b2 = 16

Take the square root of each side:
b = {-4, 4}

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